GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Oct 2019, 17:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If the average (arithmetic mean) of five positive numbers is 30, how

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58453
If the average (arithmetic mean) of five positive numbers is 30, how  [#permalink]

### Show Tags

01 Jan 2018, 10:43
00:00

Difficulty:

35% (medium)

Question Stats:

77% (01:19) correct 23% (01:05) wrong based on 29 sessions

### HideShow timer Statistics

If the average (arithmetic mean) of five positive numbers is 30, how many of the numbers are greater than 30?

(1) None of the five numbers is equal to 30.
(2) Three of the numbers are equal to 20.

_________________
Retired Moderator
Joined: 22 Aug 2013
Posts: 1428
Location: India
Re: If the average (arithmetic mean) of five positive numbers is 30, how  [#permalink]

### Show Tags

10 Jan 2018, 22:54
Bunuel wrote:
If the average (arithmetic mean) of five positive numbers is 30, how many of the numbers are greater than 30?

(1) None of the five numbers is equal to 30.
(2) Three of the numbers are equal to 20.

Lets say the numbers are a, b, c, d, e. Given that average = 30, so their sum = a+b+c+d+e = 30*5 = 150

(1) None of the five numbers is equal to 30. Its possible that a=b=c=d=25, and e=50 (here one number is > 30). Its also possible that a=b=c=20 and d=e=45 (here two numbers are > 30). So we cant say how many numbers are > 30. Insufficient.

(2) Lets say a=b=c=20, then d+e=90. Here both d & e could be 45 each (so both > 30) or we could have d=30, e=60 (so one number > 30). So we cant say how many numbers are > 30. Insufficient.

Combining the two statements, say a=b=c=20. Thus d+e=90, and no number could be 30. Here also we could have both d/e greater than 30 (say d=e=45), or we could have only one number > 30 (say d=25, e=65). Again we cant determine how many numbers are > 30. So Insufficient.

Re: If the average (arithmetic mean) of five positive numbers is 30, how   [#permalink] 10 Jan 2018, 22:54
Display posts from previous: Sort by

# If the average (arithmetic mean) of five positive numbers is 30, how

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne