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24 Oct 2019, 01:39
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:05) correct
19%
(01:35)
wrong
based on 72
sessions
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If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
24 Oct 2019, 03:17
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Bunuel
If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
p + r /2 = n
p + r = 2n..................1
again,
r + s/2 = 3n
r + s = 6n ..................2
s + r = 6n
r + p = 2n
...........................deduct
s - p = 4n.
A is the correct answer.
24 Oct 2019, 08:20
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Bunuel
If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
\(\frac{p + r}{2} = n\)
Or, \(p + r = 2n\)
Or, \(p = 2n - r\)
And, \(\frac{r + s}{2}= 3n\)
Or, \(r + s = 6n\)
Or, \(s = 6n - r\)
Now, \(s – p = ( 6n - r ) - ( 2n - r )\)
Or, \(s – p = 6n - r - 2n + r\)
Or, \(s – p = 4n\), Answer must be (A)
