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# If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0

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Math Expert
Joined: 02 Sep 2009
Posts: 53063
If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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03 Dec 2015, 04:59
00:00

Difficulty:

5% (low)

Question Stats:

96% (00:35) correct 4% (01:16) wrong based on 203 sessions

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If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then x =

A. –4
B. –3
C. –2
D. –1
E. 0

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Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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03 Dec 2015, 05:09
(x+2 + x+4 + x+6)/3 = 0
=>3x + 12 = 0
=>x = -4

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Joined: 11 Sep 2015
Posts: 3446
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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03 Dec 2015, 10:10
Bunuel wrote:
If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then x =

A. –4
B. –3
C. –2
D. –1
E. 0

Skywalker18's approach is the one I would have taken, but we can also TEST THE ANSWER CHOICES

A) x = -4
The three values become (-4 + 2), (-4 + 4), and (-4 + 6)
Simplify to get: -2, 0 and 2
The average = (-2 + 0 + 2)/3 = 0/3 = 0
Perfect!

Cheers,
Brent
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Intern
Joined: 27 Apr 2015
Posts: 11
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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03 Dec 2015, 20:53
1
Bunuel wrote:
If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then x =

A. –4
B. –3
C. –2
D. –1
E. 0

As it is an evenly spaced set with odd number of elements, hence the mean will be the middle term which is x+4 and as given

x+4 = 0
=> x = -4

Director
Joined: 24 Nov 2015
Posts: 507
Location: United States (LA)
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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29 Apr 2016, 04:37
If average of 3 numbers is equal to 0 then there total is also equal to 0

$$\frac{(x+2+x+4+x+6)}{3}$$ = 0

$$3x+12=0$$
$$3x=-12$$
$$x=-4$$

Director
Joined: 24 Nov 2015
Posts: 507
Location: United States (LA)
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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29 Apr 2016, 04:38
If average of 3 numbers is equal to 0 then there total is also equal to 0

$$\frac{(x+2+x+4+x+6)}{3}$$ = 0

$$3x+12=0$$
$$3x=-12$$
$$x=-4$$

Non-Human User
Joined: 09 Sep 2013
Posts: 9878
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0  [#permalink]

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11 Mar 2018, 10:09
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Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0   [#permalink] 11 Mar 2018, 10:09
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