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If the average of 5 numbers is 36 and the average of four of those...

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Joined: 18 Apr 2017
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WE: Corporate Finance (Energy and Utilities)
If the average of 5 numbers is 36 and the average of four of those...  [#permalink]

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New post Updated on: 16 Oct 2017, 10:15
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If the average of 5 numbers is 36 and the average of four of those numbers is 34, then what is the value of the fifth number?

(A) 2
(B) 34
(C) 35
(D) 36
(E) 44

Originally posted by robertops on 16 Oct 2017, 10:09.
Last edited by Bunuel on 16 Oct 2017, 10:15, edited 1 time in total.
Added the OA.
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Joined: 02 Sep 2009
Posts: 50772
Re: If the average of 5 numbers is 36 and the average of four of those...  [#permalink]

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New post 16 Oct 2017, 10:15
1
robertops wrote:
If the average of 5 numbers is 36 and the average of four of those numbers is 34, then what is the value of the fifth number?

(A) 2
(B) 34
(C) 35
(D) 36
(E) 44


The average of 5 numbers is 36 --> the sum of 5 numbers is 5*36 = 180;
The average of 4 numbers is 34 --> the sum of 4 numbers is 4*34 = 136.

The difference = the omitted number = 180 - 136 = 44.

Answer: E.
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Re: If the average of 5 numbers is 36 and the average of four of those...  [#permalink]

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New post 16 Oct 2017, 10:19
We know that the average of 5 numbers = 36, so (a + b + c + d + e)/5 = 36 and we also know that the average of 4 of the numbers is 34, so (a + b + c + d)/4 = 34. We can solve for (a + b + c +d) = 136 using the second equation. We can then substitute (a + b + c + d) into the first equation and solve for e. (136+e)/5=36 => 136+e=180 and therefore e=44. Choice E
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Re: If the average of 5 numbers is 36 and the average of four of those... &nbs [#permalink] 16 Oct 2017, 10:19
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