MathRevolution wrote:
[GMAT math practice question]
Attachment:
5.30.png
If the distances between each pair of consecutive ticks are equal, what is the value of x?
\(A. 2^{12}\)
\(B. 3(2^{10})\)
\(C. 5(2^{10})\)
\(D. (2^{13})\)
\(E. 3(2^{12})\)
If the distances between each pair of consecutive ticks are equal, we can write:
2^11 - 2^10 = x - 2^11We must solve this equation for x....
Add 2^11 to both sides: 2^11 + 2^11 - 2^10 = x
Combine the two 2^11's to get: 2(2^11) - 2^10 = x
Rewrite 2 as 2^1 to get: (2^1)(2^11) - 2^10 = x
Simplify to get: 2^12 - 2^10 = x
Factor our 2^10 to get: 2^10(2^2 - 1) = x
Evaluate to get: 2^10(4 - 1) = x
Simplify to get: 2^10(3) = x
Answer: B
Cheers,
Brent
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76% (01:08) correct 
