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# If the length of a certain rectangle is 2 greater than the

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Intern
Joined: 14 May 2008
Posts: 41
If the length of a certain rectangle is 2 greater than the  [#permalink]

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18 Jun 2008, 08:48
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100% (00:14) correct 0% (00:00) wrong based on 39 sessions

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If the length of a certain rectangle is 2 greater than the width of the rectangle, what is the
perimeter of the rectangle?
(1) The length of each diagonal of the rectangle is 10.
(2) The area of the rectangular region is 48.

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Director
Joined: 23 Sep 2007
Posts: 620

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18 Jun 2008, 09:07
1
D

statement 1: it is a 3-4-5 triangle
statement 2: 6 * 8 = 48
Intern
Joined: 14 May 2008
Posts: 41

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18 Jun 2008, 09:17
Yes It is D!
But Can you explain please How did you quickly recognize that it is 3 4 5 triangle with sides multiplied by 2?

I picked B at first...
SVP
Joined: 30 Apr 2008
Posts: 1633
Location: Oklahoma City
Schools: Hard Knocks

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Updated on: 18 Jun 2008, 10:26
1
I realized it was a 6-8-10 triangle because, first the hypotnuse given is 10, and we know that the height is 2 more than the base, so 6 (base) and 8 (height) fit perfectly.

The GMAT doesn't want to give us impossible questions to answer. The authors are as aware fo the time constraints as we are (well, maybe not quite as aware!).

Take the time to learn those $$3-4-5, 1-1-sqrt{2}, 1-sqrt{3}-2$$ triangles because so often, the triangles on the exam will fit perfectly into one of these. It's not the knowledge of the triangles the GMAT really tests, its recognizing the significance of the data presented to you.

Also, realize that an equilateral trianle is made up of 2, 30-60-90 triangles. My percentages may be off a bit, but I would say geometry is 90% recognizing relationships and 10% doing the actual math!

quantum wrote:
Yes It is D!
But Can you explain please How did you quickly recognize that it is 3 4 5 triangle with sides multiplied by 2?

I picked B at first...

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J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a.

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Originally posted by jallenmorris on 18 Jun 2008, 09:38.
Last edited by jallenmorris on 18 Jun 2008, 10:26, edited 2 times in total.
Manager
Joined: 11 Apr 2008
Posts: 99
Location: Chicago

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Updated on: 18 Jun 2008, 11:25
3
quantum wrote:
If the length of a certain rectangle is 2 greater than the width of the rectangle, what is the
perimeter of the rectangle?
(1) The length of each diagonal of the rectangle is 10.
(2) The area of the rectangular region is 48.

First, define the variables:
Width =w
Length = w+2

So therefore the question is asking “what is 4w+4” or simply put, “what is w?”

(1) if the diagonal is 10, this is the hypotenuse of one of the two triangles that make the rectangle. Using the Pythagorean theorem, we can say (w+2)^2 + w^2 = 100^2
--> 2w^2 + 4w +4 = 100
--> w^2 + 2w -48 = 0
--> therefore w = -8 or 6 (can’t be a negative number so w =6 and w+2 =8) --> SUFFICIENT

(2) This states that (w+2)*w = 48 --> (L*W=area)
--> w^2 + 2w -48 = 0 (this is the same equation we get in statement (1) therefore SUFFICIENT)

_________________
Factorials were someone's attempt to make math look exciting!!!

Originally posted by brokerbevo on 18 Jun 2008, 10:15.
Last edited by brokerbevo on 18 Jun 2008, 11:25, edited 1 time in total.
Intern
Joined: 14 May 2008
Posts: 41

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18 Jun 2008, 10:22
brokerbevo

Kudo to you friend!
Thank You!
Intern
Joined: 14 Jun 2008
Posts: 7

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18 Jun 2008, 10:43
what do you guys think about logic of one equeation one variable...

http://www.drgmat.com/forums/viewtopic.php?f=9&t=52&p=99#p99

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Posts: 13271
Re: If the length of a certain rectangle is 2 greater than the  [#permalink]

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15 Sep 2018, 14:39
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Re: If the length of a certain rectangle is 2 greater than the   [#permalink] 15 Sep 2018, 14:39
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