Bunuel wrote:

If the length of each of the sides of three square garden plots is increased by 50%, by what percent is the sum of the areas of the three plots increased?

(A) 375%

(B) 200%

(C) 150%

(D) 125%

(E) 50%

Use one squareAreas all increase identically. Percent increase from 3 areas summed, to sum of areas' increases, is not different from percent increase of one area to one area increased.

Use one square.

Original area = \(s^2\) = x

Each length is increased by 50%, so

New area is

(1.5s)(1.5s) =

2.25\(s^2\), \(s^2\) = x

New area: 2.25x

By what percent did area increase?

\(\frac{new - old}{old} * 100\)

Percent increase:

\(\frac{2.25x - x}{x}\) =\(\frac{1.25x}{x} = 1.25 * 100 = 125\)%

ANSWER D

_________________

In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"