If the number of square units in the area of a circle is A and the nu

Given,

A > C + 3

If we start substituting values for r, we get that after r=3, the equation holds good. Thus we arrive at an unique value of r =3. Hence Option D should be the answer right?

Can you please explain how we took \(A = π*r^2\) (area of the circle) and \(C = 2πr\) (circumference of the circle)
I think A & C actually are as below,

\(Number-of-square-units-in-the-circle, A = \frac{Area-of-the-circle}{area-of-each-square-unit}\) = \(\frac{πr^2}{a^2}\)

Similarly, for \(number-of-units-on-the-circumference-of-the-circle, C = \frac{total-circumference-of-the-circle}{length-of-each-unit-on-the-circumference}\) = \(\frac{2πr}{c}\)

Where, a = side of each square and c = length of each unit on the circumference

What I did was,
Statement 1: \(\frac{A}{C} = \frac{3}{2}\)
\((\frac{π*r^2}{a^2})/(\frac{2πr}{c})\) = 3/2
\(\frac{c*r}{2a^2}\) = \(\frac{3}{2}\)
\(r = \frac{3a^2}{c}\)

So, r(radius of the circle) depends on the area of each square unit and length of each circumference unit, which we do not know, hence Insufficient

Statement2:
\(A > C + 3\)
\(\frac{πr^2}{a^2}\) > \(\frac{2πr}{c}\) + 3

Here also, r(radius of the circle) depends on the area of each square unit and length of each circumference unit, which we do not know, hence Insufficient

Even both statements together are not helpful for the same reason, hence Insufficient option E

Please explain where my understanding is incorrect.

I appreciate mate who wrote this problem, but he missed in terms of language. Such convoluted and ambiguous language is banned in GMAT.

Your understanding is completely valid. And if someone who has solved this problem might have attempted earlier over another forum.