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# If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered

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If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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19 Jan 2014, 23:50
1
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75% (01:43) correct 25% (01:49) wrong based on 939 sessions

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

Problem Solving
Question: 48
Category: Arithmetic Operations on rational numbers
Page: 68
Difficulty: 550

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If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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19 Jan 2014, 23:50
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SOLUTION

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

The least common denominator for all the fractions above is 48:

$$\frac{17}{24}=\frac{34}{48}$$, $$\frac{1}{2}=\frac{24}{48}$$, $$\frac{3}{8}=\frac{18}{48}$$, $$\frac{3}{4}=\frac{36}{48}$$, $$\frac{9}{16}=\frac{27}{48}$$.

The numerators in descending order are: 36, 34, 27, 24, 18. The middle number is 27, which corresponds to $$\frac{9}{16}=\frac{27}{48}$$.

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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jan 2014, 00:36
[quote="Bunuel"]The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

17/24, 1/2, 3/8, 3/4, and 9/16 - Multiply all the fractions by 48 we get: 34, 24, 18, 36, 27

So 36 is the greatest which is 3/4
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jan 2014, 02:00
2
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

Problem Solving
Question: 48
Category: Arithmetic Operations on rational numbers
Page: 68
Difficulty: 550

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

Take LCM of denominators and get common denominator to all fractions so that you can compare the numerators and arrange in the increasing or decreasing order

LCM of denominators is 48

fractions can be rewritten as
34/48,24/48,18/48,36/48,27/48.
now arrange them
18/48,24/48,27/48,34/48,36/48
hence the middle element is 27/48=9/16
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jan 2014, 20:27
1
1
Easiest way to solve this type of question is to find a common multiplier for denominators of all the given number.
As we can see that the Common Factor for all the denominators- 24,2,4,8,16 is 48 .
Multiply each number by 48-
(17/24)*48 = 34
(1/2)*48 = 24
(3/8)*48 = 18
(3/4)*48 = 36
(9/16)*48 =27

So the given number becomes - 34,24,18,36,27

In descending order - 36,34,27,24,18

So mid-number is 27 .
Now again to get the required answer divide it by 48 -> 27/48 = 9/16

Note: Although the explanation may look lengthy but when we do it pen-paper it will not take more that 15 sec.
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jan 2014, 21:34
2
Approach 1:
Here, taking LCM for all the denominators, as others suggested, would be a good idea.

Approach 2:
Alternatively, if we are little good at approximation, looking at the numbers, we can say that 3/8 is the least and 3/4 is the greatest. Comparing 17/24 and 9/16 will be the slightly trickiest thing in this problem.

9/16 will be a little more than half(1/2).
17/24 will be a little less than 3/4 as 18/24 will give 3/4.

So, if we arrange from greatest to least, the order will be 3/4, 17/24, 9/16, 1/2, 3/8. Since we are asked for the middle element, 9/16 will be the answer.

Ans is (E).
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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21 Jan 2014, 04:58
1
Ans should be (e)..9/16
We can see the other nos relative to 1/2 i.e. 50%.
Just by seeing numerator and denominator 3/4 and 3/8 can be placed on either side of 1/2. 17/24 and 9/16 are definitely greater than 1/2.
So, to check which no comes in 3rd place, we can individually compute their values and see that 9/16 is smaller than 17/24.
So 9/16 must be at the 3rd spot and thus, the middle no.
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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23 Jan 2014, 06:23
1
Correct Sequence in descending order should be
3/4 ,17/24,9/16,1/2,3/8
hence middle term is 9/16

Find the common denominator then compare.
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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25 Jan 2014, 11:50
SOLUTION

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

The least common denominator for all the fractions above is 48:

$$\frac{17}{24}=\frac{34}{48}$$, $$\frac{1}{2}=\frac{24}{48}$$, $$\frac{3}{8}=\frac{18}{48}$$, $$\frac{3}{4}=\frac{36}{48}$$, $$\frac{9}{16}=\frac{27}{47}$$.

The numerators in descending order are: 36, 34, 27, 24, 18. The middle number is 27, which corresponds to $$\frac{9}{16}=\frac{27}{47}$$.

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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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26 Apr 2015, 23:06
1
Answer is E, I spent a little bit too much time on this though.

I made a number line and put in the obvious ones. The "problem" was deciding between 9/16 and 17 24 -> I realized I could reach a common denominator and it became clear which was bigger.
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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27 Oct 2016, 11:16
Finding a common denominator is the easiest way to solve this problem:

All we need to do is get to the third number of the sequence and we have our answer (because the third is the median of the set)

18/48, 24/48, 27/48...

So the middle of the set is 27/48 = 9/16
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jul 2017, 20:31
Bunuel wrote:
SOLUTION

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

The least common denominator for all the fractions above is 48:

$$\frac{17}{24}=\frac{34}{48}$$, $$\frac{1}{2}=\frac{24}{48}$$, $$\frac{3}{8}=\frac{18}{48}$$, $$\frac{3}{4}=\frac{36}{48}$$, $$\frac{9}{16}=\frac{27}{47}$$.

The numerators in descending order are: 36, 34, 27, 24, 18. The middle number is 27, which corresponds to $$\frac{9}{16}=\frac{27}{47}$$.

My least common denominator is coming out to be 96. How did we arrive at 48?

Thank You!
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Posts: 58444
Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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20 Jul 2017, 20:45
nandetapuri wrote:
Bunuel wrote:
SOLUTION

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

The least common denominator for all the fractions above is 48:

$$\frac{17}{24}=\frac{34}{48}$$, $$\frac{1}{2}=\frac{24}{48}$$, $$\frac{3}{8}=\frac{18}{48}$$, $$\frac{3}{4}=\frac{36}{48}$$, $$\frac{9}{16}=\frac{27}{47}$$.

The numerators in descending order are: 36, 34, 27, 24, 18. The middle number is 27, which corresponds to $$\frac{9}{16}=\frac{27}{47}$$.

My least common denominator is coming out to be 96. How did we arrive at 48?

Thank You!

Isn't 48 divisible by 24, 2, 8, 4, and 16?

Basically we need to find the LCM of 24 = 2^3*3 and 16 = 2^4, which is 3*2^4 = 48.
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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03 Sep 2018, 18:55
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be

(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16

We can express each fraction using a common denominator. The LCD here is 48, so we have:

17/24 = 34/48, 1/2 = 24/48, 3/8 = 18/48, 3/4 = 36/48 and 9/16 = 27/48

In ascending order, we have:

18/48, 24/48, 27/48, 34/48, 36/48

So the middle number is 27/48, or 9/16.

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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered  [#permalink]

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03 Apr 2019, 12:38
Fraction to percentage would be quicker

We just need to know the following for any decimal to fraction to percentage conversion

$$\frac{1}{2}$$ = (50%, .05) ,$$\frac{1}{3}$$ = (33.3%, .3333) ,$$\frac{1}{4}$$ = (25%, .25) ,$$\frac{1}{5}$$ = (20%, .2) $$\frac{1}{6}$$ = (16.66%, .1666) ,$$\frac{1}{7}$$ =(14.28%, .1428) ,$$\frac{1}{8}$$ =(12.5%, .125) ,$$\frac{1}{9}$$ = (11.1%, .111) ,$$\frac{1}{10}$$ = (10%,.1),$$\frac{1}{11}$$ = (9.1%, .0909) ,$$\frac{1}{13}$$ = (7.7%, .077) ,$$\frac{1}{17}$$ = (5.9%, .059) ,$$\frac{1}{19}$$ = (5.3%, .053) ,$$\frac{1}{23}$$ = (4.3%, .0435) ,$$\frac{1}{29}$$ = (3.40%, .0345) ,$$\frac{1}{31}$$ = (3.2%, .0323)

$$\frac{17}{24}$$ = 68%
$$\frac{1}{2}$$ = 50%
$$\frac{3}{8}$$= 36%
$$\frac{3}{4}$$= 75%
$$\frac{9}{16}$$= 54%

75>68>54>50>36
So D>A>E>B>C
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Re: If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered   [#permalink] 03 Apr 2019, 12:38
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