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Caas
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Caas
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Caas
I don't know the OA, sorry
Taking (1) and (2) together I came to the system:
x>(3/4)*y
x>y
0<x<=1
0<y<=1

How can we solve it?

x- prob (train)
y - prob (drive)


You're right...we cannot resolve it, and, hence, the answer should be E.
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AugiTh
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Caas
If the probability that Valerie gets to work on time is higher when she takes the train than when she drives, is the probability that Valerie gets to work on time when she bicycles greater than 0.5 ?

(1) The probability that Valerie gets to work on time when she bicycles is more than half the probability that she gets to work on time when she drives.

(2) The probability that Valerie gets to work on time when she bicycles is two-thirds the probability that she gets to work on time when she takes the train.


I go in for 'A'

From question

P(t) >p(d)
Is P(b) > 0.5

Statement1
P(b) > 0.5 * P(d)

For P(b) > 0.5 (as per question), P(d) must be greater than 1 but this cannot be. (Probability always less than or equal to 1)
Hence P(b) is not greater than 1/2

Statement2
P(b) = 2/3 P(t)
as it is: insuff!!!!



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