siddhantvarma
If the product of √x and √y is an integer and the total number of factors of y/3 is odd, which of the following must be true?
I. The total number of factors of x is odd.
II. The total number of factors of x is even.
III. The total number of factors of 3x is odd.
(A) I only (B) II only (C) III only (D) I and III only (E) II and III onlySince, number of factors of \(\frac{y}{3}\) are odd => y = (perfect square)*3
Therefore, \(\sqrt{y}\) = \(\sqrt{(perfect square)*3}\) = \(integer * \sqrt{3}\)
Now, for \(\sqrt{x} * \sqrt{y}\) to be an integer, x needs to have one 3 with any perfect square so that when \(\sqrt{x}\) and \(\sqrt{y}\) are multiplied the \(\sqrt{3}\) of \(\sqrt{y}\) gets multiplied with \(\sqrt{3}\) of \(\sqrt{x}\) and the square root goes away giving us an integer.
So, x = 3 * (any perfect square).
Now, we look at the statements,
I. Since x = 3 * (any perfect square), the number of factors of x will be a multiple of 2 (\(3^1\) => 1+1 = 2); it cannot be odd.
II. As we proved above, total number of factors of x has to be even.
III. 3x = \(3^2\) * (any perfect square), the number of factors will be 3 * any odd number = odd number. So this also has to be true.
Answer E.