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Bunuel
If the radius of a cylinder is half the length of the edge of a cube, and the height of the cylinder is equal to the length of the edge of the cube, what is the ratio of the volume of the cube to the volume of the cylinder?


A. \(\frac{2}{\pi}\)

B. \(\frac{\pi}{4}\)

C. \(\frac{4}{\pi}\)

D. \(\frac{\pi}{2}\)

E. 4


Let edge of cube be 4, so radius of cylinder is 2 and height is 4.

using given relation we find ratio to be = 4*4*4/pi*2*2*4 = answer option C
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Bunuel
If the radius of a cylinder is half the length of the edge of a cube, and the height of the cylinder is equal to the length of the edge of the cube, what is the ratio of the volume of the cube to the volume of the cylinder?


A. \(\frac{2}{\pi}\)

B. \(\frac{\pi}{4}\)

C. \(\frac{4}{\pi}\)

D. \(\frac{\pi}{2}\)

E. 4


We can let x = the length of the edge of the cube. Thus, the volume of the cube is x^3. Furthermore, the radius of the cylinder is x/2, and the height of the cylinder is x. Since the volume of a cylinder is V = πr^2h, the volume of the cylinder is:

V = π(x/2)^2 * x

V = π(x^2/4) * x

V = x^3 * π/4

Thus, the ratio of the volume of the cube to the cylinder is:

x^3/(x^3 * π/4)

1/(π/4)

4/π

Answer: C
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