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If the rectangular box shown here is 6 inches wide, 8 inches long

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If the rectangular box shown here is 6 inches wide, 8 inches long  [#permalink]

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New post 15 Mar 2018, 07:28
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A
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D
E

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Question Stats:

91% (01:03) correct 9% (01:47) wrong based on 31 sessions

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If the rectangular box shown here is 6 inches wide, 8 inches long and 7 inches high. What is the distance, in inches, between points A and B?

(A) \(\sqrt{21}\)

(B) 9

(C) 2\(\sqrt{21}\)

(D) \(\sqrt{149}\)

(E) 3\(\sqrt{21}\)

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Re: If the rectangular box shown here is 6 inches wide, 8 inches long  [#permalink]

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New post 15 Mar 2018, 07:34
itisSheldon wrote:
If the rectangular box shown here is 6 inches wide, 8 inches long and 7 inches high. What is the distance, in inches, between points A and B?
Attachment:
Capture1.JPG

(A) \(\sqrt{21}\)
(B) 9
(C) 2\(\sqrt{21}\)
(D) \(\sqrt{149}\)
(E) 3\(\sqrt{21}\)




AB is the longest distance in the box or it is the diagonals..
D = \(\sqrt{8^2+7^2+6^2}=\sqrt{64+49+36}=\sqrt{149}\)

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Re: If the rectangular box shown here is 6 inches wide, 8 inches long  [#permalink]

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New post 15 Mar 2018, 07:53
itisSheldon wrote:
Image
If the rectangular box shown here is 6 inches wide, 8 inches long and 7 inches high. What is the distance, in inches, between points A and B?

(A) \(\sqrt{21}\)

(B) 9

(C) 2\(\sqrt{21}\)

(D) \(\sqrt{149}\)

(E) 3\(\sqrt{21}\)

Attachment:
Capture1.JPG


\(Diagonal = \sqrt{8^2 +6^2 + 7^2}\)

Answer must be (D) \(\sqrt{149}\)
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Re: If the rectangular box shown here is 6 inches wide, 8 inches long  [#permalink]

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New post 15 Mar 2018, 07:59
In a cuboid, always remember that there is two type of diagonal, one is called Body/Space diagonal. other is called the side diagonal.

BODY/SPACE DIAGONAL is the longest distance between any two points in the cuboid, it is the line joining the opposite most vertex.

In this question, AB is Body diagonal.

Hence Answer is (8^2+6^2+7^2)^0.5 = 149^0.5 (D)
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Re: If the rectangular box shown here is 6 inches wide, 8 inches long   [#permalink] 15 Mar 2018, 07:59
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