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If the sides of a square are doubled in length, the area of the origin

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If the sides of a square are doubled in length, the area of the origin  [#permalink]

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New post 02 Dec 2014, 09:11
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A
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E

Difficulty:

  35% (medium)

Question Stats:

60% (01:01) correct 40% (00:55) wrong based on 258 sessions

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Re: If the sides of a square are doubled in length, the area of the origin  [#permalink]

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New post 02 Dec 2014, 10:24
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Let the original square have sides of length L and the new square have sides of length 2L.

The resulting areas are L^2 for the original square and 4L^2 for the new square (as the length of the side is square to get the area).

The original square's area is L^2/4L^2 or 25% of the new square's area. Choice A
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Re: If the sides of a square are doubled in length, the area of the origin  [#permalink]

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New post 02 Dec 2014, 19:50
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Answer = A) 25%

Say side of original square = 1

Area\(= 1^2 = 1\)

New square side is doubled = 2

Area \(= 2^2 = 4\)

Area of original square (=1) is \(\frac{1}{4}\) times area of new square (=4)

Percentage \(= \frac{1}{4} * 100 = 25%\)
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Re: If the sides of a square are doubled in length, the area of the origin  [#permalink]

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New post 03 Dec 2014, 07:55
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Re: If the sides of a square are doubled in length, the area of the origin  [#permalink]

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New post 16 Sep 2018, 06:43
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Re: If the sides of a square are doubled in length, the area of the origin   [#permalink] 16 Sep 2018, 06:43
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