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If the width of the rectangle above is increased by 50 percent and the

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Kudos [?]: 129035 [0], given: 12187

If the width of the rectangle above is increased by 50 percent and the [#permalink]

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New post 04 Oct 2017, 11:17
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If the width of the rectangle above is increased by 50 percent and the length remains the same, by what percent will the area of the rectangle be increased?

(A) 50%
(B) 100%
(C) 150°
(D) 200°
(E) cannot be determined from the information given


[Reveal] Spoiler:
Attachment:
2017-10-04_1124.png
2017-10-04_1124.png [ 1.53 KiB | Viewed 300 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 129035 [0], given: 12187

Manager
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B
Status: Preparing
Joined: 05 May 2016
Posts: 63

Kudos [?]: 11 [0], given: 149

Location: India
Concentration: International Business, Finance
Re: If the width of the rectangle above is increased by 50 percent and the [#permalink]

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New post 04 Oct 2017, 12:05
Bunuel wrote:
Image
If the width of the rectangle above is increased by 50 percent and the length remains the same, by what percent will the area of the rectangle be increased?

(A) 50%
(B) 100%
(C) 150°
(D) 200°
(E) cannot be determined from the information given


[Reveal] Spoiler:
Attachment:
2017-10-04_1124.png


New area will be 1.5xy where x is width and y is length.
Old area is xy.
(1.5xy-xy)/xy*100=50%

Answer should be A

Kudos [?]: 11 [0], given: 149

Director
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Joined: 22 May 2016
Posts: 819

Kudos [?]: 266 [0], given: 552

If the width of the rectangle above is increased by 50 percent and the [#permalink]

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New post 04 Oct 2017, 15:25
Bunuel wrote:
Image
If the width of the rectangle above is increased by 50 percent and the length remains the same, by what percent will the area of the rectangle be increased?

(A) 50%
(B) 100%
(C) 150°
(D) 200°
(E) cannot be determined from the information given


[Reveal] Spoiler:
Attachment:
2017-10-04_1124.png

Assume x = 10 and y = 4. (Choose easily multiplied numbers. For y, choose a number that, when multiplied by 1.5 or \(\frac{3}{2}\), yields an integer.)

Original area = (L * W) = 40

Width increases by 50 percent. New width is \((4)*\frac{3}{2} = 6\)

New area = (L * W) = 10 * 6 = 60

Percent increase in area =

\(\frac{New - Old}{Old} * 100\)

\(\frac{60 - 40}{40} =(\frac{20}{40}) * 100\) = 50 percent

ANSWER A

Algebra might be faster (not by much). Typically, both lengths increase. There are more multipliers, often squared. Here, just one length increases:

Original area = (y)(x)
New area = (1.5y)(x)

Percent increase:

\(\frac{1.5yx - 1yx}{yx} =
\frac{.5}{1} * 100\) = 50 percent

Kudos [?]: 266 [0], given: 552

If the width of the rectangle above is increased by 50 percent and the   [#permalink] 04 Oct 2017, 15:25
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