fozzzy wrote:

If there are B boys and G girls in a club, can the girls be divided equally among 6 teams with no girls left over?

(1) If there were 4 fewer girls then the number of girls would be twice the number of boys

(2) If the number of boys were 2 less than twice the actual number of boys, then the boys could be divided equally among 6 teams with no boys left over.

Simplify Q: Is G a multiple of 6?

Stmt 1:

G-4 = 2B

G = 2B + 4

When B=1, G=6 => YES

When B=2, G=8 => NO

Therefore, not sufficient!

Stmt 2:

2B-2/6 = int x

B = 3(x) +1

B could be 1, 4, 7..

No info about G, hence, not sufficient!

Stmt 1 + Stmt 2:

Plug stmt 2's values in stmt 1 equation. All of them show that G is multiple of 6. Hence, sufficient!

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