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Difficulty:
25%
(medium)
Question Stats:
78% (02:11) correct
22%
(02:12)
wrong
based on 1140
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If there are B boys and G girls in a club, can the girls be divided equally among 6 teams with no girls left over?
(1) If there were 4 fewer girls, then the number of girls would be twice the number of boys.
(2) If the number of boys were 2 less than twice the actual number of boys, then the boys could be divided equally among 6 teams with no boys left over.
ID 07612
(1) If there were 4 fewer girls, then the number of girls would be twice the number of boys.
(2) If the number of boys were 2 less than twice the actual number of boys, then the boys could be divided equally among 6 teams with no boys left over.
ID 07612
12 Mar 2013, 03:54
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If there are B boys and G girls in a club, can the girls be divided equally among 6 teams with no girls left over?
The question basically asks whether G is a multiple of 6.
(1) If there were 4 fewer girls then the number of girls would be twice the number of boys --> G-4=2B. If B=1, then G=6 and the answer is YES but if B=2, then G=8 and the answer is NO. Not sufficient.
(2) If the number of boys were 2 less than twice the actual number of boys, then the boys could be divided equally among 6 teams with no boys left over. This statement implies that 2B-2 is a multiple of 6. No info about G. Not sufficient.
(1)+(2) From (2) we have that 2B-2=6k --> B=3k+1. Thus from (1) we have that G-4=2(3k+1) --> G=6k+6=6(k+1) --> G IS a multiple of 6. Sufficient.
Answer: C.
Hope it's clear.
The question basically asks whether G is a multiple of 6.
(1) If there were 4 fewer girls then the number of girls would be twice the number of boys --> G-4=2B. If B=1, then G=6 and the answer is YES but if B=2, then G=8 and the answer is NO. Not sufficient.
(2) If the number of boys were 2 less than twice the actual number of boys, then the boys could be divided equally among 6 teams with no boys left over. This statement implies that 2B-2 is a multiple of 6. No info about G. Not sufficient.
(1)+(2) From (2) we have that 2B-2=6k --> B=3k+1. Thus from (1) we have that G-4=2(3k+1) --> G=6k+6=6(k+1) --> G IS a multiple of 6. Sufficient.
Answer: C.
Hope it's clear.
General Discussion
16 Jul 2015, 10:13
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Question: "Is G/6 = int?"
(1) Insufficient
G – 4 = 2B
(2) Insufficient.
(2B – 2)/6 = int
You are not telling me anything about girls!
(1 & 2) Using Substitution
(G – 4 – 2)/6 = int
(G – 6)/6 = int
Split fraction --> G/6 – 1 = integer --> G/6 = integer + 1.
And since integer + 1 = another integer, then G/6 = another integer
(1) Insufficient
G – 4 = 2B
(2) Insufficient.
(2B – 2)/6 = int
You are not telling me anything about girls!
(1 & 2) Using Substitution
(G – 4 – 2)/6 = int
(G – 6)/6 = int
Split fraction --> G/6 – 1 = integer --> G/6 = integer + 1.
And since integer + 1 = another integer, then G/6 = another integer
