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Natalya Khimich
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old_dream_1976
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BG
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Hallo,
Agree with old dream, numbers are more than 2 so B)
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remgeo
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old_dream_1976
trivikram
old_dream_1976
Natalya Khimich
If there are more than two numbers is a certain list, is each number in the list equal to 0?
1) Product of any two numbers in the list is equal to 0.
2)The sum of any two numbers in the list is equal to 0.

I think B

-1 + 1 =0

0+0=0

So B is ruled out

there are more than 2 numbers - and sum of all is equal to zero


It doesnt say, sum of ALL nos is 0.
It says sum of any 2 nos is 0. In that case, your situation does not hold.

So it has to be B.
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Professor
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has to be B.

from i, if list consists numbers 0, 0, and 1, product of any two numbers is 0.
from ii, list must contain more than 2 numbers. therefore, the numbers must be all 0s.
so suff and B is it.
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shevy
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Agree with B :wink:
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Dilshod
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It is B, because:
St.1 insuff: consider 0,0,1 or 0,0,0.
St 2 suff: since there are more than 2numbers, the sum of any 2 numbers in the set can equal to 0 only if each member of the set is 0.
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Natalya Khimich
If there are more than two numbers is a certain list, is each number in the list equal to 0?
1) Product of any two numbers in the list is equal to 0.
2)The sum of any two numbers in the list is equal to 0.


B

(If it was just 2 numbers then it would be C.. but if there are more than 2 numbers, then there's no way to get 0 for any two additions unless all are 0)
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HongHu
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Good point. To prove it, try three numbers. a+b=0, b+c=0, a+c=0. Add them up you get 2(a+b+c)=0 and thus a+b+c=0.



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