Last visit was: 09 Jul 2025, 01:52 It is currently 09 Jul 2025, 01:52
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,078
Own Kudos:
18,724
 [9]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,078
Kudos: 18,724
 [9]
If two integers x and y such x>y are selected at random between -8 and 16 May 2017, 01:33
1
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

25% (medium)

Question Stats:

78% (01:43) correct 22% (02:27) wrong based on 161 sessions

History

Date
Time
Result
Not Attempted Yet
If two integers x and y such x>y are selected at random between -8 and 11, inclusive, how many cases are possible?

A. 150
B. 180
C. 190
D. 210
E. 240
ShowHide Answer
Official Answer
C
User avatar
quantumliner
User avatar
Joined: 24 Apr 2016
Last visit: 26 Sep 2018
Posts: 244
Own Kudos:
752
 [1]
Given Kudos: 48
Posts: 244
Kudos: 752
 [1]
If two integers x and y such x>y are selected at random between -8 and 16 May 2017, 14:48
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If X is -8, then the possible values for y are (-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11)

So there are 19 combinations possible, when x is -8

Similarly, if x is -7, then y can take 18 values.

So the total number of combinations = 19+18+17+16+15+..+3+2+1 = 19/2 * (19+1) = 19 * 10 = 190

Answer is c
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,078
Own Kudos:
18,724
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,078
Kudos: 18,724
If two integers x and y such x>y are selected at random between -8 and 18 May 2017, 01:08
Kudos
Add Kudos
Bookmarks
Bookmark this Post
==> Since two integers from -8 to 11 are being randomly selected and x>y, you use combination. Thus, the number of integers from -8 to 11 becomes 11-(-8)+1=20, so 20, then 20C2=(20)(19)/2!=190.

The answer is C.
Answer: C
User avatar
nks2611
User avatar
Joined: 24 Oct 2016
Last visit: 06 Apr 2020
Posts: 190
Own Kudos:
70
Given Kudos: 89
Location: India
Concentration: Finance, International Business
Schools: IIMB
GMAT 1: 550 Q42 V28
GPA: 3.96
WE:Human Resources (Retail Banking)
Schools: IIMB
GMAT 1: 550 Q42 V28
Posts: 190
Kudos: 70
If two integers x and y such x>y are selected at random between -8 and 22 May 2017, 03:24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
the answer is C

see we need to select two integers between -8 to 11( inclusive) that are total 20 integers there where x>y , so we can choose like this 20ways(y) * 19 ways(X) =380ways but the order does not matter here means whether we choose x first or y first the order is same so divide with 2 such as 380/2= 190 ways to select .

if you liked it press kudos
User avatar
gmatsnow
User avatar
Joined: 16 Mar 2022
Last visit: 21 Mar 2024
Posts: 12
Own Kudos:
28
Given Kudos: 33
Posts: 12
Kudos: 28
If two integers x and y such x>y are selected at random between -8 and 28 Apr 2023, 13:11
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MathRevolution, I'm not sure I understand this question. If X is > Y, couldn't X never be -8 and Y could never be 11 in the -8 to 11 range?

Would this not make the answer less than 190?
User avatar
SaquibHGMATWhiz
User avatar
GMATWhiz Representative
Joined: 23 May 2022
Last visit: 12 Jun 2024
Posts: 623
Own Kudos:
653
 [1]
Given Kudos: 6
Location: India
GMAT 1: 760 Q51 V40
Expert
Expert reply
GMAT 1: 760 Q51 V40
Posts: 623
Kudos: 653
 [1]
If two integers x and y such x>y are selected at random between -8 and 29 Apr 2023, 00:21
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MathRevolution
If two integers x and y such x>y are selected at random between -8 and 11, inclusive, how many cases are possible?

A. 150
B. 180
C. 190
D. 210
E. 240
Solution:

  • Since x>y, therefore y cannot be 11 and x cannot be -8

  • If x = 11, the possible values of y are 10, 9, 8, ...1, 0, -1, -2...-7, -8 i.e., 19 values
  • If x = 10, the possible values of y are 9, 8, ...1, 0, -1, -2...-7, -8 i.e., 18 values
  • ..
  • ..
  • If x = -7, the possible values of y is -8 i.e., 1 value

  • Total values \(=19+18+17+...+2+1=\frac{19\times 20}{2}=190\)

Hence the right answer is Option C
Moderators:
Bunuel
Math Expert
102604 posts
Krunaal
PS Forum Moderator
679 posts