abs8
Bunuel
If v ≠ 0, is |w| < |v|?
(1) w/v < 1 --> if \(w=1\) and \(v=2\) the answer is YES but if \(w=-2\) and \(v=1\) the answer is NO. Not sufficient.
(2) w^2/v^2 < 1 --> since \(v^2>0\) then we can safely cross multiply: \(w^2<v^2\) --> \(|w|<|v|\). Sufficient.
Answer: B.
why not cross multiply statement 1, why only 2?
We cannot multiply w/v < 1 by v and write w < v because we don't know the sign of v. If v is positive, then yes, we'd get w < v (keep the sign when multiplying by positive value) but if v is negative, then when we multiply by negative value we should flip the sign and we'd get w > v (recall that we should flip the sign of an inequality if we multiply/divide it by negative value)..
Never multiply (or reduce) an inequality by a variable (or the expression with a variable) if you don't know its sign.
For (2) v^2 must be positive so it's safe to multiply by it.