gmatbusters wrote:

If vertex P in square PQRS is pinned and square PQRS is rotated about vertex P, what is the number of degrees the square must be rotated until the first time that vertex Q will be in the position where vertex S is now?

A) 45

B) 90

C)135

D)180

E) 270

Since I answered the question originally, the phrasing has changed.

Original wording:

**Quote:**

If vertex P in square PQRS is pinned and square PQRS is rotated clockwise about vertex P, what is the number of degrees the square must be rotated until the first time that vertex Q will be in the position where vertex S is now?

New wording:

**Quote:**

If vertex P in square PQRS is pinned and square PQRS is rotated about vertex P, what is the number of degrees the square must be rotated until the first time that vertex Q will be in the position where vertex S is now?

"Clockwise" has been removed.

I may be mistaken, but

it seems as if we have two answers.

If we rotate the square on the pivot point of P in one direction, as in my diagram below, the answer is

90°If we were to rotate the square on the pivot point of P in the other direction, the answer would be

270°(In case there is confusion about the discussion of labeling vertices . . .

Originally, vertices labeled out of alphabetical order were acceptable.

As clarified by the author above, vertices may not be labeled out of alphabetical order.)

I do not quite understand the diagram drawn by

gmatbusters , so I drew my own.

My diagram and that by

gmatbusters may well be identical, but "in the same position" is clarified in my diagram.

If "in the same position" means "directly below vertex P," and

if we rotate the square about the anchor point P in the same direction as I did below,

then I suspect this depiction is the way to explain an answer of 90°

Attachment:

qqqqqqqqq.jpg [ 65 KiB | Viewed 339 times ]
_________________

In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"