Forget the conventional way to solve DS questions.
We will solve this DS question using the variable approach.DS question with 1 variable: Let the original condition in a DS question contain 1 variable. Now, 1 variable would generally require 1 equation for us to be able to solve for the value of the variable.
We know that each condition would usually give us an equation, and Since we need 1 equation to match the numbers of variables and equations in the original condition, the logical answer is D.
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Let’s apply the 3 steps suggested previously. [Watch lessons on our website to master these 3 steps]
Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.
We have to find whether \(v^2 * m^3 * t^(-4)\) > 0 ? where vmt ≠ 0.=> \( \frac{(v^2 * m^3) }{ t^(4)}\) > 0
=> \(v^2\) and \(t^4 \)will always be positive and hence this inequality will hold TRUE if \(m^3\) > 0. That means m > 0.
We have to check is m > 0?
Second and the third step of Variable Approach: From the original condition, we have 1 variable (m).To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.Let’s take look at each condition separately.Condition(1) tells us that \(m > v^2\) .=> 'm' is greater than a positive number (\(v^2\)) and hence m > 0 - YES
Since the answer is a unique YES , condition(1) alone is sufficient by CMT 1.Condition(2) tells us that \(m > t^(-4)\) .=> 'm' is greater than a positive number (\(\frac{1 }{ t^4}\)) and hence m > 0 - YES
Since the answer is a unique YES , condition(2) alone is sufficient by CMT 1. Each condition alone is sufficient.So, D is the correct answer.Answer: DSAVE TIME: By Variable Approach, when you know that we need 1 equation, we will directly check each condition to be sufficient. We will save time in checking the conditions individually.