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Bunuel
If \(w = \sqrt{\frac{1}{16}}\), \(x = \sqrt[3]{\frac{1}{1000}}\) and \(y = (\frac{1}{4})^{(-2)}\) then

A. w < x < y
B. x < w < y
C. y < x < w
D. y < w < x
E. x < y < w

\(w = \sqrt{\frac{1}{16}}\)= \(\frac{1}{4}\)

\(x = \sqrt[3]{\frac{1}{1000}}\) = \(\frac{1}{10}\)

\(y = (\frac{1}{4})^{(-2)}\) = 16

Hence B
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Hi Bunuel,

Why didn't we have the negative root of w?
In that case w will be +1/4 and -1/4.
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basabidas
Hi Bunuel,

Why didn't we have the negative root of w?
In that case w will be +1/4 and -1/4.

\(\sqrt{...}\) is the square root sign, a function (called the principal square root function), which cannot give negative result. So, this sign (\(\sqrt{...}\)) always means non-negative square root.


The graph of the function f(x) = √x

Notice that it's defined for non-negative numbers and is producing non-negative results.

TO SUMMARIZE:
When the GMAT provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the non-negative root. That is:

\(\sqrt{9} = 3\), NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;
Similarly \(\sqrt{\frac{1}{16}} = \frac{1}{4}\), NOT +1/4 or -1/4.


Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).
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Bunuel
If \(w = \sqrt{\frac{1}{16}}\), \(x = \sqrt[3]{\frac{1}{1000}}\) and \(y = (\frac{1}{4})^{(-2)}\) then

A. w < x < y
B. x < w < y
C. y < x < w
D. y < w < x
E. x < y < w

Simplifying, we have:

w = 1/4

x = 1/10

y = 4^2 = 16

Thus, x < w < y.

Answer: B
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