Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 0808:00 AM PDT
-08:30 AM PDT
Join the special YouTube live-stream for selecting the winners of GMAT Club MBA Scholarships sponsored by Juno live. Watch who gets these coveted MBA scholarships offered by GMAT Club and Juno.
05 Jul 2019, 09:49
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
67% (02:46) correct
33%
(02:28)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
If quadrilateral WORT is a rectangle, and polygon SUVNPQ is a regular hexagon, what is the ratio of x to y?
A) \(1\)
B) \(\frac{2\sqrt{3}}{3}\)
C) \(\frac{4}{3}\)
D) \(\frac{3}{2}\)
E) \(\frac{3\sqrt{2}}{2}\)
Archit3110
05 Jul 2019, 10:02
Kudos
Bookmarks
giving a try
the hexagon will have 6 equilateral ∆ let each have side 'a' so height of ∆ ; would be √3a/2 and y would be √3a
also ∆TSU is 30:60:90 so 2x=a ; x=a/2 and TU ; a/2
so side x ; a/2+a+a/2 ; 2a
so ratio of x/y ; 2a/√3a or say 2*√3/3
IMO B
the hexagon will have 6 equilateral ∆ let each have side 'a' so height of ∆ ; would be √3a/2 and y would be √3a
also ∆TSU is 30:60:90 so 2x=a ; x=a/2 and TU ; a/2
so side x ; a/2+a+a/2 ; 2a
so ratio of x/y ; 2a/√3a or say 2*√3/3
IMO B
GMATPrepNow
05 Jul 2019, 10:33
Kudos
Bookmarks
Let the side of hexagon = a
ST=y/2= a*sin60
y=\(\sqrt{3}*a\)
x=UT+UV+VW= 2a*cos30+a= (2*a/2)+x=2a
x/y= 2a/\(\sqrt{3}*a\)= \(\frac{2}{\sqrt{3}}\)
x/y= \(2\sqrt{3}/3\)
IMO B
ST=y/2= a*sin60
y=\(\sqrt{3}*a\)
x=UT+UV+VW= 2a*cos30+a= (2*a/2)+x=2a
x/y= 2a/\(\sqrt{3}*a\)= \(\frac{2}{\sqrt{3}}\)
x/y= \(2\sqrt{3}/3\)
IMO B
GMATPrepNow
