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If x = (0.08)^2, y = 1/(0.08)^2 and z = (1 - 0.08)^2 -1, which of the

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If x = (0.08)^2, y = 1/(0.08)^2 and z = (1 - 0.08)^2 -1, which of the  [#permalink]

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New post 13 Jun 2005, 16:34
3
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A
B
C
D
E

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100% (00:07) correct 0% (00:00) wrong based on 24 sessions

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:) Hello
Plz have a look to the attachement thanks

which of the following is true ?
(A) x = y = z
(B) y < z < x
(C) z < x < y
(D) y < x and x = z
(E) x < y and x = z

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Re: If x = (0.08)^2, y = 1/(0.08)^2 and z = (1 - 0.08)^2 -1, which of the  [#permalink]

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New post 13 Jun 2005, 16:57
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x = (0.08)^2, y = 1/x, and z = (1- 0.08)^2 - 1.

So, you can see that x is a very small but positive number and z is a negative number. So, z < x.

Solving for y will give us 100^2/8^2, which is a large positive number.

So, z < x < y and I will go with choice C.
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Re: If x = (0.08)^2, y = 1/(0.08)^2 and z = (1 - 0.08)^2 -1, which of the  [#permalink]

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New post 01 Jul 2018, 23:28
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Re: If x = (0.08)^2, y = 1/(0.08)^2 and z = (1 - 0.08)^2 -1, which of the &nbs [#permalink] 01 Jul 2018, 23:28
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