Walkabout wrote:
\((\frac{x+1}{x-1})^2\)
If x ≠ 0 and x ≠ 1, and if x is replaced by 1/x everywhere in the expression above, then the resulting expression is equivalent to
A. \((\frac{x+1}{x-1})^2\)
B. \((\frac{x-1}{x+1})^2\)
C. \(\frac{x^2+1}{1-x^2}\)
D. \(\frac{x^2-1}{x^2+1}\)
E. \(-(\frac{x-1}{x+1})^2\)
Another quick hack to solve this type of question is via number substitution which makes it 0
Put X=-1 in all the options and you would only option A as same
Since X#0 & X#1 , we can X= -1
now when it is replaced by 1/X essentially it is still -1, Only Option A is giving ans as 0 ( Sames as question equation)
Correct me if I am wrong