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12 Jun 2018, 21:36
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
95% (00:51) correct
5%
(01:44)
wrong
based on 88
sessions
History
Date
Time
Result
Not Attempted Yet
If \(x \neq 0\), then \(\frac{x + 7}{7x} - \frac{1}{x} =\)
A. \(\frac{x+6}{6x}\)
B. \(\frac{x+6}{7x}\)
C. \(\frac{-6x + 7}{7x}\)
D. \(\frac{1}{7}\)
E. \(-\frac{1}{7}\)
A. \(\frac{x+6}{6x}\)
B. \(\frac{x+6}{7x}\)
C. \(\frac{-6x + 7}{7x}\)
D. \(\frac{1}{7}\)
E. \(-\frac{1}{7}\)
12 Jun 2018, 21:45
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Solution
Given:
- • x ≠ 0
To find:
- • The value of the expression \(\frac{x + 7}{7x} - \frac{1}{x}\)
Approach and Working:
If we simplify the expression, we get
- • \(\frac{x + 7}{7x} - \frac{1}{x}\)
= \(\frac{x + 7-7}{7x}\)
= \(\frac{x}{7x}\)
= \(\frac{1}{7}\) [dividing by x, as x ≠ 0]
Hence, the correct answer is option D.
Answer: D
12 Jun 2018, 22:11
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Simplifying would be an easy thing to do, if that looks tough then the next easy option would be to substitute value.
Put X = 1.
Only C and D satisfies. Now one of these two is the answer. To narrow down further
Lets Put X = 2.
Only Option D stands.
Hence 'D'.
Put X = 1.
Only C and D satisfies. Now one of these two is the answer. To narrow down further
Lets Put X = 2.
Only Option D stands.
Hence 'D'.
