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505-555 Level|   Algebra|      
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Bunuel
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If x ≠ 0, what is the value of k? 03 Apr 2018, 21:16
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A
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15% (low)

Question Stats:

75% (01:09) correct 25% (01:44) wrong based on 179 sessions

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If x ≠ 0, what is the value of k?

(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

(2) \(\frac{k}{x} = 2\)
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A
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kunalcvrce
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If x ≠ 0, what is the value of k? 03 Apr 2018, 21:54
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Bunuel
If x ≠ 0, what is the value of k?

(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

(2) \(\frac{k}{x} = 2\)

From1:since x ≠ 0.
dividing x from both side
\(\frac{3}{4} + \frac{k}{3} = \frac{1}{}\)

one variable one equation sufficient.

from2:
two variable one equation ,insufficient.

hence A
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If x ≠ 0, what is the value of k? 04 Apr 2018, 15:19
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Bunuel
If x ≠ 0, what is the value of k?

(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

(2) \(\frac{k}{x} = 2\)


(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

As x ≠ 0 &and can't be zero actually), then we can cancel out x

\(\frac{3}{4} + \frac{k}{3} =1\)

We have an equation with 1 unknown (K)

Sufficient

(2) \(\frac{k}{x} = 2\)

This a ratio so we can't determine value of k

insufficient

Answer: A
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If x ≠ 0, what is the value of k? 28 Nov 2018, 09:19
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Mo2men
Bunuel
If x ≠ 0, what is the value of k?

(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

(2) \(\frac{k}{x} = 2\)


(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

As x ≠ 0 &and can't be zero actually), then we can cancel out x

\(\frac{3}{4} + \frac{k}{3} =1\)

We have an equation with 1 unknown (K)

Sufficient

(2) \(\frac{k}{x} = 2\)

This a ratio so we can't determine value of k

insufficient

Answer: A




Can you provide some clarity on how you eliminated X from the equation without simply assuming x = 1? Thx.
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T1101
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If x ≠ 0, what is the value of k? 06 Dec 2018, 08:14
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chowarth
Mo2men
Bunuel
If x ≠ 0, what is the value of k?

(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

(2) \(\frac{k}{x} = 2\)


(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)

As x ≠ 0 &and can't be zero actually), then we can cancel out x

\(\frac{3}{4} + \frac{k}{3} =1\)

We have an equation with 1 unknown (K)

Sufficient

(2) \(\frac{k}{x} = 2\)

This a ratio so we can't determine value of k

insufficient

Answer: A




Can you provide some clarity on how you eliminated X from the equation without simply assuming x = 1? Thx.

\(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\) If you now multiply by \(x\) then: \(\frac{3}{4x}*x + \frac{k}{3x}*x = \frac{1}{x}*x\) --> Then the \(x\) in each denominator chancels out \(\frac{3}{4} + \frac{k}{3} = 1\)
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If x ≠ 0, what is the value of k? 23 Apr 2023, 01:24
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