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# If x ≠ −1/2 , then (6x^2+11x-7)/2x-1 =

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SVP
Status: Preparing GMAT
Joined: 02 Nov 2016
Posts: 1722
Location: Pakistan
GPA: 3.39
If x ≠ −1/2 , then (6x^2+11x-7)/2x-1 =  [#permalink]

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05 Mar 2017, 03:07
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Difficulty:

15% (low)

Question Stats:

90% (01:23) correct 10% (03:15) wrong based on 30 sessions

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If x ≠ −$$\frac{1}{2}$$ , then $$\frac{(6x^2+11x-7)}{(2x-1)}$$

(A) 3x + 7
(B) 3x − 7
(C) 3x + 1
(D) x + 7
(E) x − 7

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Joined: 19 Apr 2016
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GMAT 1: 570 Q48 V22
GMAT 2: 640 Q49 V28
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If x ≠ −1/2 , then (6x^2+11x-7)/2x-1 =  [#permalink]

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05 Mar 2017, 03:14
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If x ≠ −$$\frac{1}{2}$$ , then $$\frac{(6x^2+11x-7)}{(2x-1)}$$

(A) 3x + 7
(B) 3x − 7
(C) 3x + 1
(D) x + 7
(E) x − 7

$$\frac{(6x^2+11x-7)}{(2x-1)}$$

$$\frac{(6x^2+14x-3x-7)}{(2x-1)}$$

$$\frac{(2x-1)(3x+7)}{(2x-1)}$$

$$(3x+7)$$

Hence option A is correct
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If x ≠ −1/2 , then (6x^2+11x-7)/2x-1 = &nbs [#permalink] 05 Mar 2017, 03:14
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# If x ≠ −1/2 , then (6x^2+11x-7)/2x-1 =

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