Last visit was: 13 Dec 2024, 12:05 It is currently 13 Dec 2024, 12:05
Home
GMAT
Messages
Tests
Schools
Reviews
Social
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Sajjad1994
User avatar
GRE Forum Moderator
Joined: 02 Nov 2016
Last visit: 12 Dec 2024
Posts: 14,154
Own Kudos:
41,601
 []
Given Kudos: 5,905
GPA: 3.62
Products:
GMAT Club Tests Forum Quiz
Posts: 14,154
Kudos: 41,601
 []
If |x|=1 and |y|=1/3, how many possible values are there for xy? 15 Dec 2020, 02:40
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

15% (low)

Question Stats:

75% (00:49) correct 25% (00:45) wrong based on 342 sessions

History

Date
Time
Result
Not Attempted Yet
If \(|x|=1\) and \(|y|=\frac{1}{3}\), how many possible values are there for xy?

A. −13

B. 0

C. 13

D. 2

E. 4
ShowHide Answer
Official Answer
D
avatar
Jony1
avatar
Joined: 07 May 2020
Last visit: 10 Dec 2021
Posts: 3
Own Kudos:
3
 []
Given Kudos: 37
GPA: 3.67
WE:Research (Finance: Investment Banking)
Posts: 3
Kudos: 3
 []
If |x|=1 and |y|=1/3, how many possible values are there for xy? 15 Dec 2020, 03:33
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
E.4. For |x| there are - +, 2 probabilities, and 2 more for |y|. 2x2=4, there are 4 possible values for xy
User avatar
CrackverbalGMAT
User avatar
GMAT Club Legend
Joined: 03 Oct 2013
Last visit: 13 Dec 2024
Posts: 4,878
Own Kudos:
8,145
 []
Given Kudos: 224
Affiliations: CrackVerbal
Location: India
Posts: 4,878
Kudos: 8,145
 []
If |x|=1 and |y|=1/3, how many possible values are there for xy? 15 Dec 2020, 03:39
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sajjad1994
If \(|x|=1\) and \(|y|=\frac{1}{3}\), how many possible values are there for xy?

A. −13

B. 0

C. 13

D. 2

E. 4


|x| = 1, then x can be +1 or -1 and |y| = 1/3, then y can be +1/3 or -1/3


x = 1, y = 1/3, then xy = 1/3

x = -1, y = 1/3, then xy = -1/3

x = 1, y = -1/3, then xy = -1/3

x = -1, y = -1/3, then xy = 1/3


There are 2 values of xy which are +1/3 and -1/3


Option D

Arun Kumar
User avatar
BrushMyQuant
User avatar
Joined: 05 Apr 2011
Last visit: 13 Dec 2024
Posts: 2,044
Own Kudos:
2,298
 []
Given Kudos: 100
Status:Tutor - BrushMyQuant
Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
GPA: 3
WE:Information Technology (Computer Software)
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
Posts: 2,044
Kudos: 2,298
 []
If |x|=1 and |y|=1/3, how many possible values are there for xy? 28 Aug 2022, 00:04
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given that \(|x|=1\) and \(|y|=\frac{1}{3}\) and we need to find how many possible values are there for xy

|x| = 1
=> x = 1 or -1 (Watch this video to Learn about the Basics of Absolute Value)

\(|y|=\frac{1}{3}\)
=> y = \(\frac{1}{3}\) or y = -\(\frac{1}{3}\)

=> Possible values of xy are

1. x = 1, y = \(\frac{1}{3}\) => xy = 1 * \(\frac{1}{3}\) = \(\frac{1}{3}\)
2. x = 1, y = -\(\frac{1}{3}\) => xy = 1 * -\(\frac{1}{3}\) = -\(\frac{1}{3}\)
3. x = -1, y = \(\frac{1}{3}\) => xy = -1 * \(\frac{1}{3}\) = -\(\frac{1}{3}\)
4. x = -1, y = -\(\frac{1}{3}\) => xy = -1 * -\(\frac{1}{3}\) = \(\frac{1}{3}\)

=> Possible values of xy are \(\frac{1}{3}\), -\(\frac{1}{3}\)

So, Answer will be D
Hope it helps!

Watch the following video to learn How to Solve Absolute Value Problems

Moderator:
Bunuel
Math Expert
97873 posts