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C
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Difficulty:
85%
(hard)
Question Stats:
51% (02:22) correct
49%
(02:08)
wrong
based on 256
sessions
History
Date
Time
Result
Not Attempted Yet
If \(x+\frac{2}{y}= 3\),is xy an integer?
(1) x is an integer less than 3
(2) x >-1
Kudos for correct solution.Question made by me.
(1) x is an integer less than 3
(2) x >-1
Kudos for correct solution.Question made by me.
07 May 2013, 00:55
Kudos
Bookmarks
If \(x+\frac{2}{y}= 3\),is xy an integer?
I. x is an integer less than 3
x=-1 y=0.5
-1+4=3 xy = -0.5 no integer
x=2 y=2
2+1=3 xy=4 integer
Not sufficient
II. x >-1
Clearly not sufficient. x can be any decimal value >-1
I and II) x is an integer between -1 and 3 ( not included) so x is 0,1 or 2
Case x=0 xy is an integer
Case x=1 so y=1 xy integer
Case x=2 so y=2 xy integer.
Sufficient C
I. x is an integer less than 3
x=-1 y=0.5
-1+4=3 xy = -0.5 no integer
x=2 y=2
2+1=3 xy=4 integer
Not sufficient
II. x >-1
Clearly not sufficient. x can be any decimal value >-1
I and II) x is an integer between -1 and 3 ( not included) so x is 0,1 or 2
Case x=0 xy is an integer
Case x=1 so y=1 xy integer
Case x=2 so y=2 xy integer.
Sufficient C
General Discussion
vinaymimani
The answer is C for me as well......
as you can find out the value of 1 variable x or y if you have the value of one variable on hand. ..& then you can find out whether xy is an integer or not.
stmt 1... is clearly insufficient as it says that x<3.. & from this the value of xy can be non-integer or integer. Therefore, Insufficient
stmt 2... is clearly insufficient as it says that x>-13..& from this as well the value of xy can be non-integer or integer. Therefore, Insufficient.
From 1+2 ...... we have a a definite range I,e.; \(-1<x<3\). & for all the value of x in this range the solution of xy must be integer as well. Therefore, C is sufficient.
