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Bunuel
eybrj2
If x = 4 and y = 16, then \sqrt{x + y/xy} is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E 1

\(\sqrt{\frac{x+y}{xy}}=\sqrt{\frac{4+16}{4*16}}=\sqrt{\frac{20}{4*16}}=\sqrt{\frac{5}{16}}\approx{\sqrt{\frac{4}{16}}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\).

Answer: B.

P.S. Please format the questions correctly. Thank you.


Hi Bunuel,

in your final step

\sqrt{\frac{5}{16}} = 2.73 / 4

2.73 is approx 3,
then answer becomes 3/4.

Why are we not solving it in this way?
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Bunuel
eybrj2
If x = 4 and y = 16, then \sqrt{x + y/xy} is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E 1

\(\sqrt{\frac{x+y}{xy}}=\sqrt{\frac{4+16}{4*16}}=\sqrt{\frac{20}{4*16}}=\sqrt{\frac{5}{16}}\approx{\sqrt{\frac{4}{16}}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\).

Answer: B.

P.S. Please format the questions correctly. Thank you.


Hi Bunuel,

in your final step

\sqrt{\frac{5}{16}} = 2.73 / 4

2.73 is approx 3,
then answer becomes 3/4.

Why are we not solving it in this way?

\(\sqrt{5}\approx 2.24\), not 2.73
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eybrj2
If x = 4 and y = 16, then \(\sqrt{\frac{x+y}{xy}}\) is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E. 1

Hi Bunuel , why my solution is not correct ? Any idea ? :)

\(\sqrt{\frac{4+16}{4*16}}\) = \(\frac{sqrt4 +sqrt16}{sqrt64}\) = \(\frac{3}{4}\)
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dave13
eybrj2
If x = 4 and y = 16, then \(\sqrt{\frac{x+y}{xy}}\) is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E. 1

Hi Bunuel , why my solution is not correct ? Any idea ? :)

\(\sqrt{\frac{4+16}{4*16}}\) = \(\frac{sqrt4 +sqrt16}{sqrt64}\) = \(\frac{3}{4}\)

Generally \(\sqrt{x+y} \neq \sqrt{x}+\sqrt{y}\). Does \(\sqrt{1+4}\) equal to \(\sqrt{1}+\sqrt{4}\)?

8. Exponents and Roots of Numbers



Check below for more:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.
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((x+y)/xy)^0.5
Substituting the value of x and y,Given expression=(20/4*16)^0.5
5^0.5/4=2.23/4 which is approximately 0.5
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Bunuel
dave13
eybrj2
If x = 4 and y = 16, then \(\sqrt{\frac{x+y}{xy}}\) is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E. 1

Hi Bunuel , why my solution is not correct ? Any idea ? :)

\(\sqrt{\frac{4+16}{4*16}}\) = \(\frac{sqrt4 +sqrt16}{sqrt64}\) = \(\frac{3}{4}\)

Generally \(\sqrt{x+y} \neq \sqrt{x}+\sqrt{y}\). Does \(\sqrt{1+4}\) equal to \(\sqrt{1}+\sqrt{4}\)?

8. Exponents and Roots of Numbers



Check below for more:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.


Hello Bunuel, i have one question which i dont understnd

What would equal \(0^0\) = 1? or = 0 ?

many thanks :)
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dave13

Hello Bunuel, i have one question which i dont understnd

What would equal \(0^0\) = 1? or = 0 ?

many thanks :)

0^0, in some sources equals to 1, some mathematicians say it's undefined. But you won't need this for the GMAT because the case of 0^0 is not tested on the GMAT.
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eybrj2
If x = 4 and y = 16, then \(\sqrt{\frac{x+y}{xy}}\) is closet to which of the following?

A. 1/3
B. 1/2
C. 3/4
D. 7/8
E. 1
\(\sqrt{\frac{x+y}{xy}}\)

= \(\sqrt{\frac{20}{64}}\)

= \(\sqrt{\frac{10}{32}}\)

= \(\sqrt{\frac{5}{16}}\)

~ \(\sqrt{\frac{4}{16}}\)

~ \(\sqrt{\frac{1}{4}}\)

~ \(\frac{1}{2}\), Answer must be (B)
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Quote:
\(\sqrt{5}\approx 2.24\), not 2.73

Bunuel why isn't 2.24/4 not close to 3/4?
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Quote:
\(\sqrt{5}\approx 2.24\), not 2.73

Bunuel why isn't 2.24/4 not close to 3/4?

2.24/4 = 0.56 while 3/4 = 0.75.
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