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If |x + 5| = 3 and |2y - 1|/3 = 5, then |x + y| could equal each of th

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Math Expert
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Joined: 02 Sep 2009
Posts: 56244
If |x + 5| = 3 and |2y - 1|/3 = 5, then |x + y| could equal each of th  [#permalink]

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New post 20 Jul 2018, 00:13
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

68% (02:09) correct 32% (02:23) wrong based on 157 sessions

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VP
VP
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D
Joined: 31 Oct 2013
Posts: 1392
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: If |x + 5| = 3 and |2y - 1|/3 = 5, then |x + y| could equal each of th  [#permalink]

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New post 20 Jul 2018, 00:25
1
Bunuel wrote:
If \(|x + 5| = 3\) and \(\frac{|2y - 1|}{3} = 5\), then |x + y| could equal each of the following EXCEPT

A. 0
B. 6
C. 8
D. 9
E. 15



Case 1:

|x+5| = 3

X= -3 or -8


Case 2 :

|2y-1| = 15

y = 8 or -7

Combination of the sum of the x and y:

|(-2) + 8| = 6

| -2 + (-7)| = 9

| -8 + 8| = 0

|-8 +(-7)| = 15

The best answer is C.
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Re: If |x + 5| = 3 and |2y - 1|/3 = 5, then |x + y| could equal each of th  [#permalink]

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New post 20 Jul 2018, 01:02
Bunuel wrote:
If \(|x + 5| = 3\) and \(\frac{|2y - 1|}{3} = 5\), then |x + y| could equal each of the following EXCEPT


|x + 5| = 3, solving we get:
x = -2, -8

|2y - 1|/3 = 5
|2y - 1| = 15, solving we get:
y = 8, -7

Combing each values of x and y , we get :
|-2+8| = 6
|-2-7| = 9
|-8+8| = 0
|-8-7| = 15, everything but option C

Hence, C
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Re: If |x + 5| = 3 and |2y - 1|/3 = 5, then |x + y| could equal each of th   [#permalink] 20 Jul 2018, 01:02
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