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If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1

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If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1  [#permalink]

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New post 28 Jul 2016, 05:29
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

81% (01:40) correct 19% (02:18) wrong based on 82 sessions

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Re: If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1  [#permalink]

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New post 28 Jul 2016, 05:53
x = a/3 + b/3^2 + c/3^3
= a/3 + b/9 + c/27
= (9a + 3b + c ) /27

Depending on whether a, b and c take 0 or 1 , the numerator can take 1 , 3 , 4 and 12
3/27 = 1/9
12/27 = 4/9
Answer D
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Re: If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1  [#permalink]

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New post 27 Dec 2018, 18:13
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Re: If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1   [#permalink] 27 Dec 2018, 18:13
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