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Re: If x and y are integers, then 1/(x + y) CANNOT be equal to [#permalink]
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Bunuel
If x and y are integers, then \(\frac{1}{x + y}\) CANNOT be equal to

A. –1
B. -1/2
C. 0
D. 1/2
E. 1
PS21235

Key property: \(\frac{j}{k} = 0\) only if \(j = 0\) and \(k \neq 0\)
Since the numerator in the fraction \(\frac{1}{x + y}\) does not equal zero \(0\), we can be certain that \(\frac{1}{x + y}\) can never equal 0.

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Re: If x and y are integers, then 1/(x + y) CANNOT be equal to [#permalink]
we know 0 is an integer. what if x=2 and Y=-2?
then the denominator will be 0. and the value of the entire equation will be 0
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Re: If x and y are integers, then 1/(x + y) CANNOT be equal to [#permalink]
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Aslamkhanshovon
we know 0 is an integer. what if x=2 and Y=-2?
then the denominator will be 0. and the value of the entire equation will be 0
When x + y = 0, then we get 1/0, which is undefined because division by 0 is not allowed. Hence, 1/0 is undefined, not 0.
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Re: If x and y are integers, then 1/(x + y) CANNOT be equal to [#permalink]
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