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26 Nov 2018, 01:10
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
56% (02:05) correct
44%
(02:01)
wrong
based on 324
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are integers, what is the value of xy ?
(1) ((x - 1)(y - 1))! = 2
(2) x < 0
M36-44
(1) ((x - 1)(y - 1))! = 2
(2) x < 0
M36-44
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25 Oct 2021, 11:02
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Bunuel
Official Solution:
If \(x\) and \(y\) are integers, what is the value of \(xy\) ?
(1) \(((x - 1)(y - 1))! = 2\)
Only \(2! = 2\), so we have that \((x - 1)(y - 1) = 2\).
Since \(x\) and \(y\) are integers, then we can have the following four cases:
\((x - 1)=2\) and \((y - 1) = 1\). This gives \(x=3\) and \(y=2\)
\((x - 1)=1\) and \((y - 1) = 2\). This gives \(x=2\) and \(y=3\)
\((x - 1)=-2\) and \((y - 1) = -1\). This gives \(x=-1\) and \(y=0\)
\((x - 1)=-1\) and \((y - 1) = -2\). This gives \(x=0\) and \(y=-1\)
First two cases gives \(xy=6\) and the last two cases give \(xy=0\)
Not sufficient.
(2) \(x < 0\)
Not sufficient.
(1)+(2) Since from (2) \(x < 0\), then from (1) we have the third or fourth case, each of which gives \(xy=0\). Sufficient.
Answer: C
General Discussion
Archit3110
Major Poster
26 Nov 2018, 18:59
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Bunuel
From 1; To valid : x=3 and y=2 it would be valid also xy=6 and at x= 0, y=-1, xy =-1 again it would be valid so in suffcient
From 2 , no y given in sufficient
From 1 & 2 we can say that x= -1 and y =0 , sufficient...
xy= -1 IMO C
