Bunuel
If x and y are none zero, is \(\frac{x^3y^5}{x^2y^3} > 0\)?
(1) x > 0
(2) y > 0
Solution: We are given that x and y are non zero
Disclaimer: assuming imaginary numbers are not part of it
We are asked if \(\frac{x^3y^5}{x^2y^3}\) is positive or not
A fraction can be positive only if both numerator and denominator are either negative or positive
An interesting thing to notice here is we have \(y^5\) and \(y^3\) in the numerator and the denominator has odd powers which mean their positive-negative nature will be the same i.e., either both negative or both positive
So, the whole \(\frac{x^3y^5}{x^2y^3}\)
being positive or not depends on the nature of \(x\) aloneStatement 1: \(x>0\)
If x is positive, we can be sure that \(\frac{x^3y^5}{x^2y^3}\) will be positive
Thus, statement 1 alone is sufficient and we can eliminate options B, C and E
Statement 2: \(y>0\)
It doesn't matter what the nature of y is
Thus, statement 2 alone is not sufficient
Hence the right answer is
Option A