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combres
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combres
If x and y are positive integers, is x an even int?

1) x(y+5) is an even int
2) 6y^2 + 41y + 25 is even int


I can't seem to find a way for (2) to be an even integer no matter what I plug in and I think it is a waste of time to factor (2)

any ideas?


1) x can be ever or odd. Try x = 2 ,y=3 and x=3 y=3

Insuff.

2) nothing about X. but it does establish that y must be odd. here is why:
6y^2+41y+25

O=odd
E=Even

6(O)+41(O) +25 ---> E+O +O --> O +O--> Even

If y is even then 6(E) +41(E) +25---> E+E+O which is NOT even.

1&2:

X can still be even or odd. If y is odd then y+5 must be even. however, if x is odd O(E)=E or E(E)=E.

Insuff.


E
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St1:
x(y+5) could be x = even or (y+5) = even or both even. Insufficient.

St2:
6y^2 + 41y + 25 = even

25 = odd

Can be 6y^2 = odd, 41y = even, 25 =odd then odd+even+odd = even.
But if 41y = even, then y must be even and y^2 = even and 6y^2 cannot be odd.

So it must be 6y^2 = even, 41y = odd, 25 = odd then even+odd+odd= even.
Now we know y = odd. But we do not know x. Insufficient.

St1 and St2:
Since we know y is odd, y+5 = even. So x(y+5) = even but x can be odd or even. Insufficient.

Ans E



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