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Re: if x and y are +ve nos. is x>y? 1) x+y<1 2) y>x^2/2 [#permalink]
GMBA85 wrote:
x2suresh wrote:
arjtryarjtry wrote:
if x and y are +ve nos. is x>y?
1) x+y<1
2) y>x^2/2.


1)
x=1/4 and y=1/2
or
x=1/2 and y=1/4
not sufficient
2)2y>x^2
x=1/2 y=1/4 (x>y) satisfies the above equation
x=1/8 y=1/4 (x<y) satisfies the above equation.
not suffcient
combined

same as 2
not suffcient

E


I concur.


I believe the correct answer is C...

Here is Why. This is an YES or NO question basically.
The questions asks which of these following statements will answer no to the question.
is x>y

so x and y are any +ve #'s so lets say we choose x= 1000 and y=2
both of the answer will come up NO. the Same thing that the question is asking for. is X>Y the answer is NO... so its C
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Re: if x and y are +ve nos. is x>y? 1) x+y<1 2) y>x^2/2 [#permalink]
Quote:
I believe the correct answer is C...

Here is Why. This is an YES or NO question basically.
The questions asks which of these following statements will answer no to the question.
is x>y

so x and y are any +ve #'s so lets say we choose x= 1000 and y=2
both of the answer will come up NO. the Same thing that the question is asking for. is X>Y the answer is NO... so its C



With this logic, if you take stmt 1, it says x + y y. But, if x = 1/3 and y = 1/2, then x (x^2)/2 . The same is true for x = 1/3 and y = 1/2. Hence, insufficient.

Combining the two also will give the same result. Hence, E.



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Re: if x and y are +ve nos. is x>y? 1) x+y<1 2) y>x^2/2 [#permalink]
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