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Bunuel
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Bunuel
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Certainly, x is an odd number since all the factors of x are odd.

9 is a odd number which is not prime. Clause I is eliminated.  

x2 will always be odd since we have already decied x  is a odd number. So, clause II is sufficient. 

We can take 15 as an example which have 3 and 5 as factor but is not the square of an odd number. So, Clause III is eliminated.

Answer: B­
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cant agree with point regarding III. 3 is a square of 1.73 which is an odd number

square of even number is always even so an odd integer cant be a square of an even number

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­If \(x\) is a positive integer and the product of any two distinct positive factors of \(x\) is odd, which of the following must be true?

I. \(x\) is an odd prime.

II. \(x^2\) is odd.

III. \(x\) is the square of an odd number.

A. I only
B. II only
C. III only
D. I and II only
E. II and III only­




Quote:
the product of any two distinct positive factors of \(x\) is odd
­
Inference: x is an odd number, as all the factors of x are odd.

Answer choice elimination

I. \(x\) is an odd prime.

All we know is that x is an odd integer. x could be a prime number, however, it is not necessary that \(x\) is a prime number.

II. \(x^2\) is odd.

We know that \(x\) is an odd integer. Hence, \(x^2\) is also odd.

III. \(x\) is the square of an odd number.

Just like I, this could be true. However, the statement is not always true.

For example: if x = 3, x is not a square of an odd number.

Option B­
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