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D
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Difficulty:
45%
(medium)
Question Stats:
63% (01:21) correct
37%
(01:12)
wrong
based on 348
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If x is a positive integer, what is the result when (x + 1)! is divided by (x - 1)! ?
(1) (x - 1)! = 720
(2) x(x + 1) = 56
(1) (x - 1)! = 720
(2) x(x + 1) = 56
29 May 2014, 04:05
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arjoban
Sol:The above expression can be written as
\(\frac{(x+1)!}{(x-1)!}\)---------> \(\frac{(x+1)*x(x-1)!}{(x-1)!}\)
So we need to find what is the result of x*(x+1)
St1: (x-1)!=720, we know 6!=720 so x=7. We can find x(x+1). Sufficient
St 2 : x*(x+1)= 56.....straight away gives what we want. Sufficient
Ans is D
27 Oct 2015, 13:28
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arjoban
Statement 1. Factorial of some number is 720=8*9*10=2*2*2*2*3*3*5=6*5*4*3*2*1 hence 6!-720 =>x=7
Statment 2. Product of two consecutive numbers is 56. 56=7*8. Again x=7 hence sufficient.
Answer D
