Bunuel
If x is an even integer and y is an odd integer, which of the following must be an even integer?
A. y/x
B. x+y
C. 3x + 2y
D. 3(x + y)
E. 2y/x
Kudos for correct
solution.
x is an even integer and y is an odd integer.
Let us look at each option one by one.
A. y/x = odd/even.
This will not even be an integer. Hence, cannot be the answer.
B. x + y = even + odd = odd
Hence, cannot be the answer.
C. 3x + 2y
x is even so 3x is also even. 2y is even irrespective of the fact that y is odd.
so, 3x + 2y = even + even = even.
Hence, this is the correct answer.
D. 3(x + y)
= odd(even +odd)
= odd(odd) = odd
Hence, cannot be the answer.
E. 2y/x
Tricky. 2y is even and x is even
so 2y/x = 2(odd)/even
For this to be an integer, x can only be equal to 2 and if x = 2 then 2y/x = y which is an odd number.
So, 2y/x can only be an integer when x = 2 and even in that case 2y/x will not be even.
Hence, this cannot be the correct answer.