0.1X = 1X*10^-2
0.02Y = 2Y*10^-3
so the quotient becomes 1X/2Y * 10
maximizing it means numerator should be as big as possible, denominator as small as possible: so x = 9 and y = 1 , based on constraints. 19/21 * 10 = 190/21 = 9 approx
AbdurRakib
If X is the hundredths digit in the decimal 0.1X and if Y is the thousandths digit in the decimal 0.02Y, where X and Y are nonzero digits, which of the following is closest to the greatest possible value of \(\frac{0.1X}{0.02Y}\)?
A. 4
B. 5
C. 6
D. 9
E. 10