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# If x is the product of the positive integers from 1 to 8,

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Manager
Joined: 03 Oct 2008
Posts: 61
If x is the product of the positive integers from 1 to 8,  [#permalink]

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07 Oct 2008, 06:07
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:55) correct 0% (00:00) wrong based on 20 sessions

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If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i3^k5^m7^p, then i + k + m + p =

A. 4
B. 7
C. 8
D. 11
E. 12

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Retired Moderator
Joined: 05 Jul 2006
Posts: 1723

### Show Tags

07 Oct 2008, 09:06
albany09 wrote:
If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i3^k5^m7^p, then i + k + m + p =

A. 4
B. 7
C. 8
D. 11
E. 12

X = 2*3*4*5*6*7*8 = (2^4)(3^2*5*7) =

I = 4 , K = 2, M = 1,P = 1 ANSWER IS 8 ........c
Intern
Joined: 28 Jan 2010
Posts: 29

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02 Mar 2010, 06:34
1
yezz wrote:
albany09 wrote:
If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i3^k5^m7^p, then i + k + m + p =

A. 4
B. 7
C. 8
D. 11
E. 12

X = 2*3*4*5*6*7*8 = (2^4)(3^2*5*7) =

I = 4 , K = 2, M = 1,P = 1 ANSWER IS 8 ........c

I think there is a mistake in your calculation.

1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

=2 x 3 x (2x2) x 5 x (3x2) x 7 x (2x2x2)
=2^7 x 3^2 x 5^1 x 7^1

Therefore the i + k + m + p = 7 + 2 + 1+ 1 = 11

Ans D.
Manager
Joined: 04 Feb 2007
Posts: 79

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04 Mar 2010, 15:31
agree, it should be 11

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Re: If x is the product of the positive integers from 1 to 8,  [#permalink]

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10 Aug 2018, 17:09
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Re: If x is the product of the positive integers from 1 to 8, &nbs [#permalink] 10 Aug 2018, 17:09
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