Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
21 Oct 2021, 08:01
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
51% (01:37) correct
49%
(01:37)
wrong
based on 161
sessions
History
Date
Time
Result
Not Attempted Yet
If \(\frac{x}{w}-\frac{x}{y}=0\), what is the value of \(y\)?
(1) \(w^2 + 4 = 4w\)
(2) \(w^2 + w - 6 = 0\)
(1) \(w^2 + 4 = 4w\)
(2) \(w^2 + w - 6 = 0\)
22 Oct 2021, 08:40
Kudos
Bookmarks
BrentGMATPrepNow
If \(\frac{x}{w}-\frac{x}{y}=0\), what is the value of \(y\)?
(1) \(w^2 + 4 = 4w\)
(2) \(w^2 + w - 6 = 0\)
(1) \(w^2 + 4 = 4w\)
(2) \(w^2 + w - 6 = 0\)
I created this question to highlight an important consideration when comparing two equivalent fractions.
If we know that \(\frac{x}{w}=\frac{x}{y}\), we can't then conclude that \(w = y\) (even though both fractions have the same numerator), since it COULD be the case that \(x = 0\), in which case we have \(\frac{0}{w}=\frac{0}{y}\).
Notice that the equation \(\frac{0}{w}=\frac{0}{y}\) holds true for all nonzero values of \(w\) and \(y\).
So, we can't necessarily conclude that \(w = y\)
Target question: What is the value of \(y\)?
Since we now know that, when \(x=0\), the given equation (\(\frac{x}{w}=\frac{x}{y}\)) holds true for all nonzero values of \(w\) and \(y\), I'm going to jump straight to....
Statements 1 and 2 combined
There are several values of \(w\), \(x\) and \(y\) that satisfy BOTH statements. Here are two:
Case a: \(w = 2\), \(x = 0\) and \(y = 2\). These values satisfy the given equation since \(\frac{0}{2}=\frac{0}{2}\)
In this case, the answer to the target question is y = 1
Case b: \(w = 2\), \(x = 0\) and \(y = 10\). These values satisfy the given equation since \(\frac{0}{2}=\frac{0}{10}\)
In this case, the answer to the target question is y = 10
Since we can’t answer the target question with certainty, the combined statements are NOT SUFFICIENT
Answer: E
Cheers,
Brent
13 Jul 2022, 20:57
Kudos
Bookmarks
I solved this the hard way and I got E
S1: found the value to be 2 for w solving via quadratic equations and then substituted into the equation. but since we dont know what x & y. this is insufficient to find Y. S1 - Insufficient.
S2: Didnt solve because again we would get w but we dont know x and y. hence insufficient.
S1& S2: we have W but dont have X & Y hence this would be insufficient.
E
BrentGMATPrepNow, is this an acceptable thought process? thank you!
S1: found the value to be 2 for w solving via quadratic equations and then substituted into the equation. but since we dont know what x & y. this is insufficient to find Y. S1 - Insufficient.
S2: Didnt solve because again we would get w but we dont know x and y. hence insufficient.
S1& S2: we have W but dont have X & Y hence this would be insufficient.
E
BrentGMATPrepNow, is this an acceptable thought process? thank you!
