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# If x > y > 0, does 3^(x + 1) + 3(2^y) = 12v?

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Re: If x > y > 0, does 3^(x + 1) + 3(2^y) = 12v? [#permalink]
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vangramz wrote:
The question seems incorrect in that we don't even need the two options The LHS is clearly an even + odd which will always be odd and the RHS is even since its a multiple of 2.

The question doesn't state that x and y are integers. Hence, we can't assume that 3^x = even and 2^y = odd.
Re: If x > y > 0, does 3^(x + 1) + 3(2^y) = 12v? [#permalink]
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