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If x=y+1 and x is a non-negative integer, is x even?

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If x=y+1 and x is a non-negative integer, is x even?  [#permalink]

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New post 25 Jan 2018, 21:49
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If \(x=y+1\) and \(x\) is a non-negative integer, is x even?

(1) \(y^2 +1\) is even.
(2) \(y\) is a negative integer.


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Re: If x=y+1 and x is a non-negative integer, is x even?  [#permalink]

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New post 25 Jan 2018, 22:26
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Given X is a non negative integer and x=y+1 so y has to be an integer.

St:1 From this we can deduce that y is odd because odd+1 is even.
And if y is odd x will be even.
Sufficient.

St:2 Given y is a negative integer and also in question stem it is given that x should be a non negative integer. So only y=-1 satisfies
For this X will be 0 and hence even.
Sufficient

IMO D


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Re: If x=y+1 and x is a non-negative integer, is x even?  [#permalink]

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New post 25 Jan 2018, 23:28
From 1: O + O= E
Therefore, y = O & X = O+O = Even
Sufficient

From 2: The only possible negative integer value of y for x to be non-negative integer given that x=y+1 is -1.
Therefore, x=-1+1=0, Even
Sufficient

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If x=y+1 and x is a non-negative integer, is x even?  [#permalink]

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New post 26 Jan 2018, 07:21
If x=y+1 and x is a non-negative integer, is x even?

(1) y^2 + 1 is even.
According to this statement, we get y ^2 is odd. now y can't be non-integer as, x = y+1 is an integer.
So, y is an odd integer (-ve or +ve integer). So, x = y+1 = odd+odd = even.
Hence, it is sufficient.
P.S, it doesn't matter whether y is -ve or +ve, eg. -1+1 = 0 (even) . 3+1 = 4 (even)
(2) y is a negative integer.
now, y is -1, x = 0 even, if y is any other integer other than -1, then x would be negative... hence it will dissatisy the question stem, which is not possible.
Hence x = 0, even
It is sufficient.
Answer is D
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If x=y+1 and x is a non-negative integer, is x even? &nbs [#permalink] 26 Jan 2018, 07:21
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