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Solution



Given:

    • \((x−y)= \sqrt{12}\)
    • \((x+y)=\sqrt{3}\)


To find:
• The value of \(x^2- y^2\).

Approach and Working:

• \(x^2- y^2= (x-y)(x+y)\)
• =\(\sqrt{12}*\sqrt{3}= \sqrt{36}= 6\)

Hence, the correct answer is option B.

Answer: B
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√12 * √3 = √12(3) = √36 = 6.

Next?
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Bunuel
If \((x - y) =\sqrt{12}\) and \((x + y) = \sqrt{3}\), what is the value of \(x^2 - y^2\)?

(A) 3
(B) 6
(C) 9
(D) 36
(E) It cannot be determined from the information given.

\(x^2 - y^2 = (x - y)(x + y)\)

So, \(x^2 - y^2 = \sqrt{12}*\sqrt{3}\)

Or, \(x^2 - y^2 = \sqrt{36}\)

Thus, \(x^2 - y^2 = 6\), Answer must be (B)
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Bunuel
If \((x - y) =\sqrt{12}\) and \((x + y) = \sqrt{3}\), what is the value of \(x^2 - y^2\)?

(A) 3
(B) 6
(C) 9
(D) 36
(E) It cannot be determined from the information given.

Let’s first factor the expression x^2 - y^2 and then substitute with the given values:

x^2 - y^2 = (x - y)(x + y) = (√12)(√3) = √36 = 6

Answer: B
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Bunuel
If \((x - y) =\sqrt{12}\) and \((x + y) = \sqrt{3}\), what is the value of \(x^2 - y^2\)?

(A) 3
(B) 6
(C) 9
(D) 36
(E) It cannot be determined from the information given.

Asked: If \((x - y) =\sqrt{12}\) and \((x + y) = \sqrt{3}\), what is the value of \(x^2 - y^2\)?

\(x^2 - y^2 = (x+y)(x-y) = \sqrt{3}*\sqrt{12} = \sqrt{36} = 6\)

IMO B
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