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C
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Difficulty:
55%
(hard)
Question Stats:
68% (02:23) correct
32%
(02:48)
wrong
based on 25
sessions
History
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Time
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Not Attempted Yet
If x+y+2>0 and 2x=-4+y, with the condition that x and y can assume only integer values; which of the following provides the possible solution to the given set of inequalities/equations?
A. x<-3, y<0
B. x>0, y<-2
C. x>-2, y>0
D. x>2, y>3
E. x>0, y>3
(adapted from Varsity Tutors)
A. x<-3, y<0
B. x>0, y<-2
C. x>-2, y>0
D. x>2, y>3
E. x>0, y>3
(adapted from Varsity Tutors)
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Updated on: 11 Sep 2022, 02:02
Originally posted by SaquibHGMATWhiz on 10 Sep 2022, 22:34.
Last edited by SaquibHGMATWhiz on 11 Sep 2022, 02:02, edited 1 time in total.
Last edited by SaquibHGMATWhiz on 11 Sep 2022, 02:02, edited 1 time in total.
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There seems to be something incorrect here.
We have, x+y+2>0 and 2x=-4+y
Let's start with y = 2x + 4.
So it seems option C should be x > - 2 and y > 0.
We have, x+y+2>0 and 2x=-4+y
Let's start with y = 2x + 4.
- The sets of values for (x, y) that are possible will be (0,4) (1, 6), (2, 8) .... when we keep on increasing x and y.
Also, the values that are possible on the other side would be (-1, 2) (-2, 0), (-3, -2) (- 4, -4) and so on.
- So if we list them they will look like " ... (-4, -4), (-3, -2), (-2, 0), (-1, 2), (0,4) (1, 6), (2, 8) ..."
Now for x + y + 2 > 0 we can say the values are (-1, 2), (0,4) (1, 6), (2, 8) ...
So it seems option C should be x > - 2 and y > 0.
11 Sep 2022, 00:07
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We also get x>-2 which makes C wrong.
