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jodeci
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 18:49
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If x + y^2 = (x+y^2)^2, what is the value of y?

1. x=y^2
2. xy^2=0



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Professor
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 19:48
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jodeci
If x + y^2 = (x+y^2)^2, what is the value of y?

1. x=y^2
2. xy^2=0
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(x + y^2) = (x+y^2)^2
(x + y^2) = (x+y^2) (x + y^2)
x + y^2 = 1

from i, x = 1/2, y = + or - 1/2. not suff.
from ii, xy^2 = 0, then either x or y = 0. if x = 0 and y = not 0, then equation (x + y^2) = (x+y^2)^2 doesnot hold true cuz no matter what the value of y is, the equation wont be equal. so from ii, y's value must be 0 to make the equation true. therefore B.
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vivek123
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 21:07
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Prof, I'm getting "E" on this :?[/b]
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shevy
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 21:35
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Professor

from ii, xy^2 = 0, then either x or y = 0. if x = 0 and y = not 0, then equation (x + y^2) = (x+y^2)^2 doesnot hold true cuz no matter what the value of y is, the equation wont be equal. so from ii, y's value must be 0 to make the equation true. therefore B.
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if x = 0: then y^2 = y^4

It will hold true if y = 1 or y = -1

Hence E

I am getting E :wink:
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 21:51
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shevy
It will hold true if y = 1 or y = -1
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i take this one.








:beat
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Professor
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 21:59
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jodeci
Answer is not E
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i messed up ii with i. yah it should be C now.
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If x + y^2 = (x+y^2)^2, what is the value of y? 1. x=y^2 2. 07 Apr 2006, 22:08
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from st 1

y= 0, +/-1/sqrt(2)

from st 2
if x= 0, then y can have multiple values.
when y = 0, x can have multiple value.
to satisfy the given equation when x = 0

y^2 = y^4 ----> y = 0 & y = +1 & -1

Now combining these two, only Y=0 satisfy both case
hence its C



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